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Sistem preoblikujemo na
-1x - 1y + 1z = 2
-2x - 3y + 2z = -2
-2x + 5y - 1z = 1
in si naredimo tabelo
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| x | y | z | 1 | faktor |
pomnožimo => |
x | y | z | 1 |
odštejemo => |
|---|
| -1 | -1 | 1 | 2 | 2 |
-2 | -2 | 2 | 4 |
| -2 | -3 | 2 | -2 | / |
-2 | -3 | 2 | -2 |
| -2 | 5 | -1 | 1 | / |
-2 | 5 | -1 | 1 |
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| x | y | z | 1 | faktor |
pomnožimo => |
x | y | z | 1 |
odštejemo => |
|---|
| -2 | -2 | 2 | 4 | / |
-2 | -2 | 2 | 4 |
| 0 | 1 | 0 | 6 | -7 |
0 | -7 | 0 | -42 |
| 0 | -7 | 3 | 3 | / |
0 | -7 | 3 | 3 |
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| x | y | z | 1 |
dobimo => |
|---|
| -2 | -2 | 2 | 4 |
| 0 | -7 | 0 | -42 |
| 0 | 0 | -3 | -45 |
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Dobimo z = 15, y = 6 in x = 7.
Nazaj
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